ATP Challenger Tour Winners: January 2025

It’s easy to forget about all the other tennis events around the tours during the month of a Grand Slam, but the opening month of the 2025 season had some interesting results on the ATP Challenger Tour.

Joao Fonseca began his stellar run to the 2nd round of the Australian Open, with a title in the opening week. Belgian young gun, Alexander Blockx won the first title of his career in Portugal, and Hamad Medjedovic made a good decision to skip Australian Open qualifying, as he also grabbed himself a title in Portugal.

Here are all the winners throughout the month of January.

December 30

Canberra 125

João Fonseca (BRA) def Ethan Quinn (USA) 6–4, 6–4        

Nouméa 100

Shintaro Mochizuki (JPN) def Moerani Bouzige (AUS) 6–1, 6–3

Nonthaburi 75

Aslan Karatsev (RUS) def Grégoire Barrère (FRA) 7–6(7–5), 7–5  

January 6

Nonthaburi Challenger II 75

Rio Noguchi (JPN) def Cui Jie (CHN) 7–6(11–9), 6–2         

Nottingham 75

Viktor Durasovic (NOR) def Henry Searle (GBR) 7–6(8–6), 3–6, 6–1           

Oeiras 75

Hamad Medjedovic (SRB) def Liam Draxl (CAN) 6–1, 6–3

January 13        

Oeiras II 100

Aleksandar Kovacevic (USA) def Zsombor Piros (HUN) 6–4, 7–6(7–4)        

Nonthaburi III 75

Brandon Holt (USA) def Vít Kopřiva (CZE) 6–3, 6–2           

Tigre 50

Juan Pablo Varillas (PER) def Daniel Vallejo (PAR) 6–4, 6–4                         

January 20

Quimper 125

Sascha Gueymard Wayenburg (FRA) def Pierre-Hugues Herbert (FRA) 6–7(3–7), 6–1, 6–2             

Oeiras III 100

Alexander Blockx (BEL) def Liam Draxl (CAN) 7–5, 6–1     

Embed from Getty Images

Punta del Este 75

Daniel Elahi Galán (COL) def Tomás Barrios Vera (CHI) 5–7, 6–4, 6–4        

January 27

Koblenz 100

Ugo Blanchet (FRA) def Luca Nardi (ITA) 6–3, 3–6, 7–6(7–5)         

Piracicaba 100

Román Andrés Burruchaga (ARG) def Facundo Mena (ARG) 7–6(10–8), 6–7(6–8), 7–6(7–4)

Brisbane 75

Tristan Schoolkate (AUS) def Marek Gengel (CZE) 7–6(7–3), 7–6(7–4)

Cleveland 75

Colton Smith (USA) def Eliot Spizzirri (USA) 6–4, 6–7(6–8), 6–3    

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